Distance from Janow Lubelski to Cesky Tesin
The shortest distance (air line) between Janow Lubelski and Cesky Tesin is 180.43 mi (290.38 km).
How far is Janow Lubelski from Cesky Tesin
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 14:24 (08.02.2025)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 14:24 (08.02.2025)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 180.43 miles which is equal to 290.38 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Cesky Tesin, Moravskoslezský kraj, Czechia