Distance from Janow Lubelski to Cockeysville
The shortest distance (air line) between Janow Lubelski and Cockeysville is 4,522.98 mi (7,279.03 km).
How far is Janow Lubelski from Cockeysville
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 03:18 (10.12.2025)
Cockeysville is located in Maryland, United States within 39° 28' 49.44" N -77° 22' 14.16" W (39.4804, -76.6294) coordinates. The local time in Cockeysville is 21:18 (09.12.2025)
The calculated flying distance from Cockeysville to Cockeysville is 4,522.98 miles which is equal to 7,279.03 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Cockeysville, Maryland, United States