Distance from Janow Lubelski to Duncan
The shortest distance (air line) between Janow Lubelski and Duncan is 5,520.29 mi (8,884.05 km).
How far is Janow Lubelski from Duncan
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 06:55 (10.12.2025)
Duncan is located in Oklahoma, United States within 34° 32' 26.88" N -98° 4' 42.6" W (34.5408, -97.9215) coordinates. The local time in Duncan is 23:55 (09.12.2025)
The calculated flying distance from Duncan to Duncan is 5,520.29 miles which is equal to 8,884.05 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Duncan, Oklahoma, United States