Distance from Janow Lubelski to Essex Junction
The shortest distance (air line) between Janow Lubelski and Essex Junction is 4,150.65 mi (6,679.83 km).
How far is Janow Lubelski from Essex Junction
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 09:19 (10.12.2025)
Essex Junction is located in Vermont, United States within 44° 29' 24.72" N -74° 53' 9.24" W (44.4902, -73.1141) coordinates. The local time in Essex Junction is 03:19 (10.12.2025)
The calculated flying distance from Essex Junction to Essex Junction is 4,150.65 miles which is equal to 6,679.83 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Essex Junction, Vermont, United States