Distance from Janow Lubelski to Evansville
The shortest distance (air line) between Janow Lubelski and Evansville is 4,986.69 mi (8,025.30 km).
How far is Janow Lubelski from Evansville
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 09:30 (10.12.2025)
Evansville is located in Indiana, United States within 37° 59' 17.16" N -88° 27' 57.24" W (37.9881, -87.5341) coordinates. The local time in Evansville is 02:30 (10.12.2025)
The calculated flying distance from Evansville to Evansville is 4,986.69 miles which is equal to 8,025.30 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Evansville, Indiana, United States