Distance from Janow Lubelski to Hauppauge
The shortest distance (air line) between Janow Lubelski and Hauppauge is 4,330.62 mi (6,969.45 km).
How far is Janow Lubelski from Hauppauge
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 20:04 (12.12.2025)
Hauppauge is located in New York, United States within 40° 49' 15.96" N -74° 47' 20.76" W (40.8211, -73.2109) coordinates. The local time in Hauppauge is 14:04 (12.12.2025)
The calculated flying distance from Hauppauge to Hauppauge is 4,330.62 miles which is equal to 6,969.45 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Hauppauge, New York, United States