Distance from Janow Lubelski to Haysville
The shortest distance (air line) between Janow Lubelski and Haysville is 5,329.32 mi (8,576.71 km).
How far is Janow Lubelski from Haysville
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 00:20 (15.12.2025)
Haysville is located in Kansas, United States within 37° 33' 53.28" N -98° 38' 50.28" W (37.5648, -97.3527) coordinates. The local time in Haysville is 17:20 (14.12.2025)
The calculated flying distance from Haysville to Haysville is 5,329.32 miles which is equal to 8,576.71 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Haysville, Kansas, United States