Distance from Janow Lubelski to Hicksville
The shortest distance (air line) between Janow Lubelski and Hicksville is 4,345.04 mi (6,992.66 km).
How far is Janow Lubelski from Hicksville
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 20:05 (12.12.2025)
Hicksville is located in New York, United States within 40° 45' 49.32" N -74° 28' 31.8" W (40.7637, -73.5245) coordinates. The local time in Hicksville is 14:05 (12.12.2025)
The calculated flying distance from Hicksville to Hicksville is 4,345.04 miles which is equal to 6,992.66 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Hicksville, New York, United States