Distance from Janow Lubelski to Jacksonville Beach
The shortest distance (air line) between Janow Lubelski and Jacksonville Beach is 5,178.63 mi (8,334.21 km).
How far is Janow Lubelski from Jacksonville Beach
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 11:10 (14.12.2025)
Jacksonville Beach is located in Florida, United States within 30° 16' 41.52" N -82° 35' 43.8" W (30.2782, -81.4045) coordinates. The local time in Jacksonville Beach is 05:10 (14.12.2025)
The calculated flying distance from Jacksonville Beach to Jacksonville Beach is 5,178.63 miles which is equal to 8,334.21 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Jacksonville Beach, Florida, United States