Distance from Janow Lubelski to Jamestown
The shortest distance (air line) between Janow Lubelski and Jamestown is 4,485.00 mi (7,217.91 km).
How far is Janow Lubelski from Jamestown
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 11:08 (14.12.2025)
Jamestown is located in New York, United States within 42° 5' 51.36" N -80° 45' 47.88" W (42.0976, -79.2367) coordinates. The local time in Jamestown is 05:08 (14.12.2025)
The calculated flying distance from Jamestown to Jamestown is 4,485.00 miles which is equal to 7,217.91 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Jamestown, New York, United States