Distance from Janow Lubelski to Jefferson Hills
The shortest distance (air line) between Janow Lubelski and Jefferson Hills is 4,601.11 mi (7,404.76 km).
How far is Janow Lubelski from Jefferson Hills
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 11:09 (14.12.2025)
Jefferson Hills is located in Pennsylvania, United States within 40° 17' 33.36" N -80° 4' 1.56" W (40.2926, -79.9329) coordinates. The local time in Jefferson Hills is 05:09 (14.12.2025)
The calculated flying distance from Jefferson Hills to Jefferson Hills is 4,601.11 miles which is equal to 7,404.76 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Jefferson Hills, Pennsylvania, United States