Distance from Janow Lubelski to Leesburg
The shortest distance (air line) between Janow Lubelski and Leesburg is 5,278.12 mi (8,494.31 km).
How far is Janow Lubelski from Leesburg
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 01:31 (17.12.2025)
Leesburg is located in Florida, United States within 28° 46' 1.92" N -82° 6' 13.68" W (28.7672, -81.8962) coordinates. The local time in Leesburg is 19:31 (16.12.2025)
The calculated flying distance from Leesburg to Leesburg is 5,278.12 miles which is equal to 8,494.31 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Leesburg, Florida, United States