Distance from Janow Lubelski to Lynn Haven
The shortest distance (air line) between Janow Lubelski and Lynn Haven is 5,339.42 mi (8,592.97 km).
How far is Janow Lubelski from Lynn Haven
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 08:27 (17.12.2025)
Lynn Haven is located in Florida, United States within 30° 14' 1.32" N -86° 21' 46.8" W (30.2337, -85.6370) coordinates. The local time in Lynn Haven is 01:27 (17.12.2025)
The calculated flying distance from Lynn Haven to Lynn Haven is 5,339.42 miles which is equal to 8,592.97 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Lynn Haven, Florida, United States