Distance from Janow Lubelski to Oakton
The shortest distance (air line) between Janow Lubelski and Oakton is 4,577.42 mi (7,366.65 km).
How far is Janow Lubelski from Oakton
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 15:36 (19.12.2025)
Oakton is located in Virginia, United States within 38° 53' 19.32" N -78° 41' 54.24" W (38.8887, -77.3016) coordinates. The local time in Oakton is 09:36 (19.12.2025)
The calculated flying distance from Oakton to Oakton is 4,577.42 miles which is equal to 7,366.65 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Oakton, Virginia, United States