Distance from Janow Lubelski to Oakville
The shortest distance (air line) between Janow Lubelski and Oakville is 5,055.12 mi (8,135.43 km).
How far is Janow Lubelski from Oakville
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 14:28 (19.12.2025)
Oakville is located in Missouri, United States within 38° 26' 52.44" N -91° 40' 48.36" W (38.4479, -90.3199) coordinates. The local time in Oakville is 07:28 (19.12.2025)
The calculated flying distance from Oakville to Oakville is 5,055.12 miles which is equal to 8,135.43 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Oakville, Missouri, United States