Distance from Janow Lubelski to Patchogue
The shortest distance (air line) between Janow Lubelski and Patchogue is 4,326.35 mi (6,962.59 km).
How far is Janow Lubelski from Patchogue
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 22:26 (19.12.2025)
Patchogue is located in New York, United States within 40° 45' 43.56" N -74° 58' 53.4" W (40.7621, -73.0185) coordinates. The local time in Patchogue is 16:26 (19.12.2025)
The calculated flying distance from Patchogue to Patchogue is 4,326.35 miles which is equal to 6,962.59 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Patchogue, New York, United States