Distance from Janow Lubelski to Peekskill
The shortest distance (air line) between Janow Lubelski and Peekskill is 4,334.11 mi (6,975.08 km).
How far is Janow Lubelski from Peekskill
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 18:22 (19.12.2025)
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 12:22 (19.12.2025)
The calculated flying distance from Peekskill to Peekskill is 4,334.11 miles which is equal to 6,975.08 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Peekskill, New York, United States