Distance from Janow Lubelski to Pikesville
The shortest distance (air line) between Janow Lubelski and Pikesville is 4,530.21 mi (7,290.67 km).
How far is Janow Lubelski from Pikesville
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 12:48 (08.01.2026)
Pikesville is located in Maryland, United States within 39° 23' 21.48" N -77° 17' 52.8" W (39.3893, -76.7020) coordinates. The local time in Pikesville is 06:48 (08.01.2026)
The calculated flying distance from Pikesville to Pikesville is 4,530.21 miles which is equal to 7,290.67 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Pikesville, Maryland, United States