Distance from Janow Lubelski to Savage
The shortest distance (air line) between Janow Lubelski and Savage is 4,805.31 mi (7,733.40 km).
How far is Janow Lubelski from Savage
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 14:37 (12.01.2026)
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 07:37 (12.01.2026)
The calculated flying distance from Savage to Savage is 4,805.31 miles which is equal to 7,733.40 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Savage, Minnesota, United States