Distance from Janow Lubelski to Seminole
The shortest distance (air line) between Janow Lubelski and Seminole is 5,361.70 mi (8,628.82 km).
How far is Janow Lubelski from Seminole
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 15:58 (21.12.2025)
Seminole is located in Florida, United States within 27° 50' 36.6" N -83° 12' 57.6" W (27.8435, -82.7840) coordinates. The local time in Seminole is 09:58 (21.12.2025)
The calculated flying distance from Seminole to Seminole is 5,361.70 miles which is equal to 8,628.82 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Seminole, Florida, United States