Distance from Janow Lubelski to Severn
The shortest distance (air line) between Janow Lubelski and Severn is 4,542.73 mi (7,310.82 km).
How far is Janow Lubelski from Severn
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 12:46 (21.12.2025)
Severn is located in Maryland, United States within 39° 8' 7.8" N -77° 18' 15.84" W (39.1355, -76.6956) coordinates. The local time in Severn is 06:46 (21.12.2025)
The calculated flying distance from Severn to Severn is 4,542.73 miles which is equal to 7,310.82 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Severn, Maryland, United States