Distance from Janow Lubelski to Shakopee
The shortest distance (air line) between Janow Lubelski and Shakopee is 4,807.61 mi (7,737.11 km).
How far is Janow Lubelski from Shakopee
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 19:47 (21.12.2025)
Shakopee is located in Minnesota, United States within 44° 46' 28.2" N -94° 31' 22.08" W (44.7745, -93.4772) coordinates. The local time in Shakopee is 12:47 (21.12.2025)
The calculated flying distance from Shakopee to Shakopee is 4,807.61 miles which is equal to 7,737.11 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Shakopee, Minnesota, United States