Distance from Janow Lubelski to Shenandoah
The shortest distance (air line) between Janow Lubelski and Shenandoah is 5,523.39 mi (8,889.04 km).
How far is Janow Lubelski from Shenandoah
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 14:02 (11.01.2026)
Shenandoah is located in Louisiana, United States within 30° 24' 6.84" N -92° 59' 52.8" W (30.4019, -91.0020) coordinates. The local time in Shenandoah is 07:02 (11.01.2026)
The calculated flying distance from Shenandoah to Shenandoah is 5,523.39 miles which is equal to 8,889.04 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Shenandoah, Louisiana, United States