Distance from Janow Lubelski to Sicklerville
The shortest distance (air line) between Janow Lubelski and Sicklerville is 4,449.52 mi (7,160.82 km).
How far is Janow Lubelski from Sicklerville
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 18:27 (21.12.2025)
Sicklerville is located in New Jersey, United States within 39° 44' 42.72" N -75° 0' 23.76" W (39.7452, -74.9934) coordinates. The local time in Sicklerville is 12:27 (21.12.2025)
The calculated flying distance from Sicklerville to Sicklerville is 4,449.52 miles which is equal to 7,160.82 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Sicklerville, New Jersey, United States