Distance from Janow Lubelski to Sioux Falls
The shortest distance (air line) between Janow Lubelski and Sioux Falls is 4,972.12 mi (8,001.85 km).
How far is Janow Lubelski from Sioux Falls
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 09:32 (24.12.2025)
Sioux Falls is located in South Dakota, United States within 43° 32' 22.56" N -97° 16' 8.04" W (43.5396, -96.7311) coordinates. The local time in Sioux Falls is 02:32 (24.12.2025)
The calculated flying distance from Sioux Falls to Sioux Falls is 4,972.12 miles which is equal to 8,001.85 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Sioux Falls, South Dakota, United States