Distance from Janow Lubelski to Summerville
The shortest distance (air line) between Janow Lubelski and Summerville is 4,988.19 mi (8,027.71 km).
How far is Janow Lubelski from Summerville
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 13:34 (14.01.2026)
Summerville is located in South Carolina, United States within 33° 0' 5.76" N -81° 49' 12.36" W (33.0016, -80.1799) coordinates. The local time in Summerville is 07:34 (14.01.2026)
The calculated flying distance from Summerville to Summerville is 4,988.19 miles which is equal to 8,027.71 km.
Janow Lubelski, Puławski, Poland
Related Distances from Janow Lubelski
Summerville, South Carolina, United States