Distance from Jefferson to Diepenbeek
The shortest distance (air line) between Jefferson and Diepenbeek is 4,395.04 mi (7,073.14 km).
How far is Jefferson from Diepenbeek
Jefferson is located in Georgia, United States within 34° 8' 14.28" N -84° 23' 52.44" W (34.1373, -83.6021) coordinates. The local time in Jefferson is 18:21 (16.11.2024)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 00:21 (17.11.2024)
The calculated flying distance from Diepenbeek to Diepenbeek is 4,395.04 miles which is equal to 7,073.14 km.
Jefferson, Georgia, United States
Related Distances from Jefferson
Diepenbeek, Arr. Hasselt, Belgium