Distance from Jefferson City to Diepenbeek
The shortest distance (air line) between Jefferson City and Diepenbeek is 4,508.09 mi (7,255.08 km).
How far is Jefferson City from Diepenbeek
Jefferson City is located in Missouri, United States within 38° 34' 3.36" N -93° 49' 26.76" W (38.5676, -92.1759) coordinates. The local time in Jefferson City is 19:25 (14.02.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 02:25 (15.02.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 4,508.09 miles which is equal to 7,255.08 km.
Jefferson City, Missouri, United States
Related Distances from Jefferson City
Diepenbeek, Arr. Hasselt, Belgium