Distance from Jefferson City to Opglabbeek
The shortest distance (air line) between Jefferson City and Opglabbeek is 4,509.10 mi (7,256.70 km).
How far is Jefferson City from Opglabbeek
Jefferson City is located in Missouri, United States within 38° 34' 3.36" N -93° 49' 26.76" W (38.5676, -92.1759) coordinates. The local time in Jefferson City is 08:01 (12.02.2025)
Opglabbeek is located in Arr. Maaseik, Belgium within 51° 2' 60" N 5° 34' 59.88" E (51.0500, 5.5833) coordinates. The local time in Opglabbeek is 15:01 (12.02.2025)
The calculated flying distance from Opglabbeek to Opglabbeek is 4,509.10 miles which is equal to 7,256.70 km.
Jefferson City, Missouri, United States
Related Distances from Jefferson City
Opglabbeek, Arr. Maaseik, Belgium