Distance from Jefferson Hills to Alexandroupoli
The shortest distance (air line) between Jefferson Hills and Alexandroupoli is 5,152.96 mi (8,292.89 km).
How far is Jefferson Hills from Alexandroupoli
Jefferson Hills is located in Pennsylvania, United States within 40° 17' 33.36" N -80° 4' 1.56" W (40.2926, -79.9329) coordinates. The local time in Jefferson Hills is 09:47 (04.03.2025)
Alexandroupoli is located in Evros, Greece within 40° 51' 0" N 25° 52' 0.12" E (40.8500, 25.8667) coordinates. The local time in Alexandroupoli is 16:47 (04.03.2025)
The calculated flying distance from Alexandroupoli to Alexandroupoli is 5,152.96 miles which is equal to 8,292.89 km.
Jefferson Hills, Pennsylvania, United States