Distance from Jefferson Hills to Assebroek
The shortest distance (air line) between Jefferson Hills and Assebroek is 3,861.91 mi (6,215.15 km).
How far is Jefferson Hills from Assebroek
Jefferson Hills is located in Pennsylvania, United States within 40° 17' 33.36" N -80° 4' 1.56" W (40.2926, -79.9329) coordinates. The local time in Jefferson Hills is 20:13 (11.02.2025)
Assebroek is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 15' 0" E (51.2000, 3.2500) coordinates. The local time in Assebroek is 02:13 (12.02.2025)
The calculated flying distance from Assebroek to Assebroek is 3,861.91 miles which is equal to 6,215.15 km.
Jefferson Hills, Pennsylvania, United States
Related Distances from Jefferson Hills
Assebroek, Arr. Brugge, Belgium