Distance from Jefferson Hills to Koekelberg
The shortest distance (air line) between Jefferson Hills and Koekelberg is 3,914.29 mi (6,299.44 km).
How far is Jefferson Hills from Koekelberg
Jefferson Hills is located in Pennsylvania, United States within 40° 17' 33.36" N -80° 4' 1.56" W (40.2926, -79.9329) coordinates. The local time in Jefferson Hills is 22:28 (14.02.2025)
Koekelberg is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 52' 0.12" N 4° 19' 59.88" E (50.8667, 4.3333) coordinates. The local time in Koekelberg is 04:28 (15.02.2025)
The calculated flying distance from Koekelberg to Koekelberg is 3,914.29 miles which is equal to 6,299.44 km.
Jefferson Hills, Pennsylvania, United States
Related Distances from Jefferson Hills
Koekelberg, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium