Distance from Jefferson Hills to Kurort Steinbach-Hallenberg
The shortest distance (air line) between Jefferson Hills and Kurort Steinbach-Hallenberg is 4,162.82 mi (6,699.41 km).
How far is Jefferson Hills from Kurort Steinbach-Hallenberg
Jefferson Hills is located in Pennsylvania, United States within 40° 17' 33.36" N -80° 4' 1.56" W (40.2926, -79.9329) coordinates. The local time in Jefferson Hills is 15:36 (28.02.2025)
Kurort Steinbach-Hallenberg is located in Schmalkalden-Meiningen, Germany within 50° 42' 2.16" N 10° 34' 0.12" E (50.7006, 10.5667) coordinates. The local time in Kurort Steinbach-Hallenberg is 21:36 (28.02.2025)
The calculated flying distance from Kurort Steinbach-Hallenberg to Kurort Steinbach-Hallenberg is 4,162.82 miles which is equal to 6,699.41 km.
Jefferson Hills, Pennsylvania, United States
Related Distances from Jefferson Hills
Kurort Steinbach-Hallenberg, Schmalkalden-Meiningen, Germany