Distance from Jefferson Hills to Lovendegem
The shortest distance (air line) between Jefferson Hills and Lovendegem is 3,878.58 mi (6,241.97 km).
How far is Jefferson Hills from Lovendegem
Jefferson Hills is located in Pennsylvania, United States within 40° 17' 33.36" N -80° 4' 1.56" W (40.2926, -79.9329) coordinates. The local time in Jefferson Hills is 04:48 (12.02.2025)
Lovendegem is located in Arr. Gent, Belgium within 51° 6' 0" N 3° 36' 0" E (51.1000, 3.6000) coordinates. The local time in Lovendegem is 10:48 (12.02.2025)
The calculated flying distance from Lovendegem to Lovendegem is 3,878.58 miles which is equal to 6,241.97 km.
Jefferson Hills, Pennsylvania, United States
Related Distances from Jefferson Hills
Lovendegem, Arr. Gent, Belgium