Distance from Jefferson Hills to Opglabbeek
The shortest distance (air line) between Jefferson Hills and Opglabbeek is 3,958.23 mi (6,370.15 km).
How far is Jefferson Hills from Opglabbeek
Jefferson Hills is located in Pennsylvania, United States within 40° 17' 33.36" N -80° 4' 1.56" W (40.2926, -79.9329) coordinates. The local time in Jefferson Hills is 23:06 (14.02.2025)
Opglabbeek is located in Arr. Maaseik, Belgium within 51° 2' 60" N 5° 34' 59.88" E (51.0500, 5.5833) coordinates. The local time in Opglabbeek is 05:06 (15.02.2025)
The calculated flying distance from Opglabbeek to Opglabbeek is 3,958.23 miles which is equal to 6,370.15 km.
Jefferson Hills, Pennsylvania, United States
Related Distances from Jefferson Hills
Opglabbeek, Arr. Maaseik, Belgium