Distance from Jefferson Hills to Sankt Polten
The shortest distance (air line) between Jefferson Hills and Sankt Polten is 4,445.92 mi (7,155.01 km).
How far is Jefferson Hills from Sankt Polten
Jefferson Hills is located in Pennsylvania, United States within 40° 17' 33.36" N -80° 4' 1.56" W (40.2926, -79.9329) coordinates. The local time in Jefferson Hills is 16:10 (11.02.2025)
Sankt Polten is located in Sankt Pölten, Austria within 48° 12' 0" N 15° 37' 0.12" E (48.2000, 15.6167) coordinates. The local time in Sankt Polten is 22:10 (11.02.2025)
The calculated flying distance from Sankt Polten to Sankt Polten is 4,445.92 miles which is equal to 7,155.01 km.
Jefferson Hills, Pennsylvania, United States
Related Distances from Jefferson Hills
Sankt Polten, Sankt Pölten, Austria