Distance from Jefferson Hills to Sint-Andries
The shortest distance (air line) between Jefferson Hills and Sint-Andries is 3,859.27 mi (6,210.90 km).
How far is Jefferson Hills from Sint-Andries
Jefferson Hills is located in Pennsylvania, United States within 40° 17' 33.36" N -80° 4' 1.56" W (40.2926, -79.9329) coordinates. The local time in Jefferson Hills is 00:08 (15.02.2025)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 06:08 (15.02.2025)
The calculated flying distance from Sint-Andries to Sint-Andries is 3,859.27 miles which is equal to 6,210.90 km.
Jefferson Hills, Pennsylvania, United States
Related Distances from Jefferson Hills
Sint-Andries, Arr. Brugge, Belgium