Distance from Jefferson Hills to Sint-Kruis
The shortest distance (air line) between Jefferson Hills and Sint-Kruis is 3,861.59 mi (6,214.62 km).
How far is Jefferson Hills from Sint-Kruis
Jefferson Hills is located in Pennsylvania, United States within 40° 17' 33.36" N -80° 4' 1.56" W (40.2926, -79.9329) coordinates. The local time in Jefferson Hills is 10:54 (12.02.2025)
Sint-Kruis is located in Arr. Brugge, Belgium within 51° 12' 42.12" N 3° 15' 0" E (51.2117, 3.2500) coordinates. The local time in Sint-Kruis is 16:54 (12.02.2025)
The calculated flying distance from Sint-Kruis to Sint-Kruis is 3,861.59 miles which is equal to 6,214.62 km.
Jefferson Hills, Pennsylvania, United States
Related Distances from Jefferson Hills
Sint-Kruis, Arr. Brugge, Belgium