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      Distance from Jefferson Hills to Sint-Martens-Lennik

      The shortest distance (air line) between Jefferson Hills and Sint-Martens-Lennik is 3,908.94 mi (6,290.83 km).

      How far is Jefferson Hills from Sint-Martens-Lennik

      Jefferson Hills is located in Pennsylvania, United States within 40° 17' 33.36" N -80° 4' 1.56" W (40.2926, -79.9329) coordinates. The local time in Jefferson Hills is 13:40 (14.02.2025)

      Sint-Martens-Lennik is located in Arr. Halle-Vilvoorde, Belgium within 50° 47' 60" N 4° 9' 0" E (50.8000, 4.1500) coordinates. The local time in Sint-Martens-Lennik is 19:40 (14.02.2025)

      The calculated flying distance from Sint-Martens-Lennik to Sint-Martens-Lennik is 3,908.94 miles which is equal to 6,290.83 km.

      Jefferson Hills, Pennsylvania, United States

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      Jefferson Hills to Brooklyn (New York)315.40 mi (507.58 km)
      Jefferson Hills to New York (New York)316.84 mi (509.90 km)
      Jefferson Hills to Queens (New York)323.72 mi (520.97 km)
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      Sint-Martens-Lennik, Arr. Halle-Vilvoorde, Belgium

      Related Distances to Sint-Martens-Lennik