Distance from Jefferson Hills to Sulzbach-Rosenberg
The shortest distance (air line) between Jefferson Hills and Sulzbach-Rosenberg is 4,249.05 mi (6,838.19 km).
How far is Jefferson Hills from Sulzbach-Rosenberg
Jefferson Hills is located in Pennsylvania, United States within 40° 17' 33.36" N -80° 4' 1.56" W (40.2926, -79.9329) coordinates. The local time in Jefferson Hills is 16:30 (03.03.2025)
Sulzbach-Rosenberg is located in Amberg-Sulzbach, Germany within 49° 30' 0" N 11° 45' 0" E (49.5000, 11.7500) coordinates. The local time in Sulzbach-Rosenberg is 22:30 (03.03.2025)
The calculated flying distance from Sulzbach-Rosenberg to Sulzbach-Rosenberg is 4,249.05 miles which is equal to 6,838.19 km.
Jefferson Hills, Pennsylvania, United States
Related Distances from Jefferson Hills
Sulzbach-Rosenberg, Amberg-Sulzbach, Germany