Distance from Jefferson Hills to Svilengrad
The shortest distance (air line) between Jefferson Hills and Svilengrad is 5,125.08 mi (8,248.02 km).
How far is Jefferson Hills from Svilengrad
Jefferson Hills is located in Pennsylvania, United States within 40° 17' 33.36" N -80° 4' 1.56" W (40.2926, -79.9329) coordinates. The local time in Jefferson Hills is 22:31 (12.02.2025)
Svilengrad is located in Haskovo, Bulgaria within 41° 46' 0.12" N 26° 11' 60" E (41.7667, 26.2000) coordinates. The local time in Svilengrad is 05:31 (13.02.2025)
The calculated flying distance from Svilengrad to Svilengrad is 5,125.08 miles which is equal to 8,248.02 km.
Jefferson Hills, Pennsylvania, United States