Distance from Jefferson Hills to Waasmunster
The shortest distance (air line) between Jefferson Hills and Waasmunster is 3,897.48 mi (6,272.38 km).
How far is Jefferson Hills from Waasmunster
Jefferson Hills is located in Pennsylvania, United States within 40° 17' 33.36" N -80° 4' 1.56" W (40.2926, -79.9329) coordinates. The local time in Jefferson Hills is 16:15 (14.02.2025)
Waasmunster is located in Arr. Dendermonde, Belgium within 51° 6' 34.92" N 4° 5' 4.92" E (51.1097, 4.0847) coordinates. The local time in Waasmunster is 22:15 (14.02.2025)
The calculated flying distance from Waasmunster to Waasmunster is 3,897.48 miles which is equal to 6,272.38 km.
Jefferson Hills, Pennsylvania, United States
Related Distances from Jefferson Hills
Waasmunster, Arr. Dendermonde, Belgium