Distance from Jefferson Valley-Yorktown to Baldwin Park
The shortest distance (air line) between Jefferson Valley-Yorktown and Baldwin Park is 2,438.84 mi (3,924.94 km).
How far is Jefferson Valley-Yorktown from Baldwin Park
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 21:25 (04.12.2025)
Baldwin Park is located in California, United States within 34° 4' 58.44" N -118° 1' 40.08" W (34.0829, -117.9722) coordinates. The local time in Baldwin Park is 18:25 (04.12.2025)
The calculated flying distance from Baldwin Park to Baldwin Park is 2,438.84 miles which is equal to 3,924.94 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Baldwin Park, California, United States