Distance from Jefferson Valley-Yorktown to Civita Castellana
The shortest distance (air line) between Jefferson Valley-Yorktown and Civita Castellana is 4,231.79 mi (6,810.40 km).
How far is Jefferson Valley-Yorktown from Civita Castellana
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 04:16 (19.03.2025)
Civita Castellana is located in Viterbo, Italy within 42° 17' 45.96" N 12° 24' 36" E (42.2961, 12.4100) coordinates. The local time in Civita Castellana is 10:16 (19.03.2025)
The calculated flying distance from Civita Castellana to Civita Castellana is 4,231.79 miles which is equal to 6,810.40 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Civita Castellana, Viterbo, Italy