Distance from Jefferson Valley-Yorktown to Civitavecchia
The shortest distance (air line) between Jefferson Valley-Yorktown and Civitavecchia is 4,212.08 mi (6,778.69 km).
How far is Jefferson Valley-Yorktown from Civitavecchia
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 03:50 (19.03.2025)
Civitavecchia is located in Roma, Italy within 42° 6' 0" N 11° 48' 0" E (42.1000, 11.8000) coordinates. The local time in Civitavecchia is 09:50 (19.03.2025)
The calculated flying distance from Civitavecchia to Civitavecchia is 4,212.08 miles which is equal to 6,778.69 km.
Jefferson Valley-Yorktown, New York, United States