Distance from Jefferson Valley-Yorktown to Fernandina Beach
The shortest distance (air line) between Jefferson Valley-Yorktown and Fernandina Beach is 850.91 mi (1,369.40 km).
How far is Jefferson Valley-Yorktown from Fernandina Beach
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 23:08 (05.12.2025)
Fernandina Beach is located in Florida, United States within 30° 39' 25.56" N -82° 32' 56.04" W (30.6571, -81.4511) coordinates. The local time in Fernandina Beach is 23:08 (05.12.2025)
The calculated flying distance from Fernandina Beach to Fernandina Beach is 850.91 miles which is equal to 1,369.40 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Fernandina Beach, Florida, United States