Distance from Jefferson Valley-Yorktown to Lakeland
The shortest distance (air line) between Jefferson Valley-Yorktown and Lakeland is 1,025.58 mi (1,650.50 km).
How far is Jefferson Valley-Yorktown from Lakeland
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 19:58 (06.12.2025)
Lakeland is located in Florida, United States within 28° 3' 20.52" N -82° 2' 43.8" W (28.0557, -81.9545) coordinates. The local time in Lakeland is 19:58 (06.12.2025)
The calculated flying distance from Lakeland to Lakeland is 1,025.58 miles which is equal to 1,650.50 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Lakeland, Florida, United States