Distance from Jefferson Valley-Yorktown to Martinsburg
The shortest distance (air line) between Jefferson Valley-Yorktown and Martinsburg is 254.57 mi (409.69 km).
How far is Jefferson Valley-Yorktown from Martinsburg
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 20:08 (08.12.2025)
Martinsburg is located in West Virginia, United States within 39° 27' 29.52" N -78° 1' 20.64" W (39.4582, -77.9776) coordinates. The local time in Martinsburg is 20:08 (08.12.2025)
The calculated flying distance from Martinsburg to Martinsburg is 254.57 miles which is equal to 409.69 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Martinsburg, West Virginia, United States