Distance from Jefferson Valley-Yorktown to Martinsville
The shortest distance (air line) between Jefferson Valley-Yorktown and Martinsville is 456.45 mi (734.58 km).
How far is Jefferson Valley-Yorktown from Martinsville
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 20:08 (08.12.2025)
Martinsville is located in Virginia, United States within 36° 40' 57.36" N -80° 8' 11.04" W (36.6826, -79.8636) coordinates. The local time in Martinsville is 20:08 (08.12.2025)
The calculated flying distance from Martinsville to Martinsville is 456.45 miles which is equal to 734.58 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Martinsville, Virginia, United States