Distance from Jefferson Valley-Yorktown to Meulebeke
The shortest distance (air line) between Jefferson Valley-Yorktown and Meulebeke is 3,578.72 mi (5,759.40 km).
How far is Jefferson Valley-Yorktown from Meulebeke
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 09:35 (25.02.2025)
Meulebeke is located in Arr. Tielt, Belgium within 50° 56' 58.92" N 3° 17' 12.84" E (50.9497, 3.2869) coordinates. The local time in Meulebeke is 15:35 (25.02.2025)
The calculated flying distance from Meulebeke to Meulebeke is 3,578.72 miles which is equal to 5,759.40 km.
Jefferson Valley-Yorktown, New York, United States
Related Distances from Jefferson Valley-Yorktown
Meulebeke, Arr. Tielt, Belgium